1/4(x-5)^2=8

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Solution for 1/4(x-5)^2=8 equation:


x in (-oo:+oo)

(1/4)*(x-5)^2 = 8 // - 8

(1/4)*(x-5)^2-8 = 0

1/4*(x-5)^2-8 = 0

1/4*(x-5)^2-8 = 0

1/4*x^2-5/2*x-7/4 = 0

1/4*x^2-5/2*x-7/4 = 0

1/2*(1/2*x^2-5*x-7/2) = 0

1/2*x^2-5*x-7/2 = 0

DELTA = (-5)^2-(-7/2*1/2*4)

DELTA = 32

DELTA > 0

x = (32^(1/2)+5)/(1/2*2) or x = (5-32^(1/2))/(1/2*2)

x = 4*2^(1/2)+5 or x = 5-4*2^(1/2)

1/2*(x+4*2^(1/2)-5)*(x-4*2^(1/2)-5) = 0

1/2*(x+4*2^(1/2)-5)*(x-4*2^(1/2)-5) = 0

( 1/2 )

1/2 = 0

x belongs to the empty set

( x+4*2^(1/2)-5 )

x+4*2^(1/2)-5 = 0 // - 4*2^(1/2)-5

x = -(4*2^(1/2)-5)

x = 5-(4*2^(1/2))

( x-4*2^(1/2)-5 )

x-4*2^(1/2)-5 = 0 // + -4*2^(1/2)-5

x = -(-4*2^(1/2)-5)

x = 5-(-4*2^(1/2))

x in { 5-(4*2^(1/2)), 5-(-4*2^(1/2)) }

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